Che 101 Homework 2-17

CHEM 101: Homework #3: Problems from Chang Chapter 3 sections 3.1-3.8 Show your work! ANSWERS 1. Chang 3.13: how many S atoms in 5.10 moles S? 5.10 moles S x (6.02x10 23 atoms S/1 mol S) = 30.7x10 23 = 3.07x10 24 atoms S 2. Chang 3.19: what is the mass in grams of 1.00x10 12 atoms of lead, Pb? 1.00x10 12 atoms Pb x (1 mol Pb/6.02x10 23 atoms Pb) x (207.2 g Pb/1 mol Pb) = 3.44x10 –10 g Other method: 1.00x10 12 atoms = 1.00x10 12 /6.02x10 23 = 1.66x10 –12 mol Pb 1.66x10 –12 mol = 1.66x10 –12 x207.2 = 3.44x10 –10 g 3. Chang 3.39: calculate the percent (%) composition of Sn and of O in SnO 2 MM of Sn O 2 is 118.7 + 2x16.0 = 150.7 g/mol. % Sn = (118.7/150.7)x100% = 78.8 % Sn. Then 100 – 78.8 = 21.2% O (of course also same answer from 32.0/150.7)x100% = 21.2 %O) 4 Chang 3.49a Find the empirical formula of a compound of mass composition 2.1% H, 65.3% O, 32.6% S. "Take 100 g compound", then 2.1 g H, 65.3 g O, 32.6 g S Mol H = (2.1/1.01)= 2.08; mol O = (65.3/16.0)= 4.08; mol S = 32.6/32.1 = 1.02

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